Permuted Multiples

There's a chance you think of 1/7 when you read this problem and immediately find the answer. But if not, it doesn't take long for the computer to tell you.

from itertools import count

for n in count(1):
    digits = set(str(n))
    for x in (2, 3, 4, 5, 6):
        if set(str(n*x)) != digits:
            break
    else:
        break
        
n

142857

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